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Solving a2 + b2 = p in $ \mathbb {Z}$ : pa2b2

pa2b2 decompose a prime integer p congruent to 1 modulo 4, as a sum of squares : p = a2 + b2. The result is the list [a,b].
Input :
Output :
indeed 17 = 42 +12

giac documentation written by Renée De Graeve and Bernard Parisse