2/ On tape :
p3(x):=x^
3
f3(x):=normal((h@p3@g)(x))
puis
f3(x)
On obtient :
(x^
3+6*x)/(3*x^
2+2)
3/ On a :
t0 = u1
t1 = f3(t0) = f3(u1) = u3
t2 = f3(t1) = f3(u3) = u9
t3 = f3(t2) = f3(u9) = u27
....donc
tn = u3n
4/Si on prend
3n 1432, on aura
| tn - l| < 10-1000
On tape :
solve(3^
n>1432.,n)
On obtient :
n>6.61...
Donc si n 7), on aura
| wn - l| < 10-1000