- 3.1 :

We have :

3.1 = 2*(1 + + + + + + ....) = 2*(1 + + ( + ))

hence = 1 and*m*= + ( + ). Hence the hexadecimal and binary representation of 3.1 is:40 (01000000), 8 (00001000), cc (11001100), cc (11001100), cc (11001100), cc (11001100), cc (11001100), cd (11001101),

the last octet is 1101, the last bit is 1, because the following digit is 1 (upper rounding). - 3. :

We have 3 = 2*(1 + 1/2). Hence the hexadecimal and binary representation of 3 is:40 (01000000), 8 (00001000), 0 (00000000), 0 (00000000), 0 (00000000), 0 (00000000), 0 (00000000), 0 (00000000)

giac documentation written by Renée De Graeve and Bernard Parisse