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2.6.24  Solving a2+b2=p in ℤ : pa2b2

pa2b2 decompose a prime integer p congruent to 1 modulo 4, as a sum of squares : p= a2+b2. The result is the list [a,b].
Input :

pa2b2(17)

Output :

[4,1]

indeed 17=42+12


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